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6x^2+7x-98=100
We move all terms to the left:
6x^2+7x-98-(100)=0
We add all the numbers together, and all the variables
6x^2+7x-198=0
a = 6; b = 7; c = -198;
Δ = b2-4ac
Δ = 72-4·6·(-198)
Δ = 4801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{4801}}{2*6}=\frac{-7-\sqrt{4801}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{4801}}{2*6}=\frac{-7+\sqrt{4801}}{12} $
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